Opracowane zadanie 3.pdf

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<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
Oblicz naprężenie gnące wału dane:
Q =1400kG
n
-1
E =2.1·10 MPa = 2.1·10 kG·cm
= 477,707 min ,
kr
5
6
-2
l/d= 22,
f= 0,04 mm = 0,004 cm
zakres podkrytyczny => ω w < ω kr
1)
m = Q/g
m = 1,4 [kG·s 2 ·cm -1 ]
= π
⋅
n
= 50 [s -1 ]
kr
2)
ω
kr
30
k
ω
3)
ω
kr =
=>
k
=
kr ⋅
m
m
k = 3500 [kG·cm -1 ]
4
π
d
4)
I =
64
4
π
⋅
d
48
E
⋅
4
⎛
3
⎞
48
E
⋅
I
3
E
⋅
π
⋅
d
3
d
64
⎜
⎝
⎟
⎠
k
=
=
=
=
E
⋅
π
⋅
d
⋅
3
3
3
3
l
l
4
l
4
l
⎛
3
⎞
4
l
⎜
⎝
⎟
⎠
d
=
k
⋅
3
3
⋅
E
⋅
π
d
Podstawiamy:
l
k = 3500 [kg·s -2 ]
6
-2
E = 2.1·10 [kG·cm ]
=
22
d
Otrzymujemy:
4
() 53
3
d
=
350000
⋅
22
=
7
6
3
⋅
π
⋅
2
⋅
10
1
k
⋅
f
⋅
l
⋅
M
P
⋅
l
⋅
α
8
⋅
k
⋅
f
⋅
l
8
⋅
k
⋅
f
⎛
l
⎞
k
⋅
0
004
4
g
5)
ϑ
=
=
=
=
=
=
22
⋅
8
⋅
⎝
⎠
g
3
3
3
2
2
W
π
d
π
d
π
d
π
d
d
π
d
x
32
32
k
3500
[kG·cm -2 ]
ϑ
=
0
224
⋅
=
0
224
⋅
=
13
,
83
2
d
56
,
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