Profile shearing capacity:
xa = $xa$; xb = $xb$.
- along axis Y
VR = 0,58 (*Kl4 jpv *)AV fd = 0,58×(*Kl4 $9.1.2$×*)$9.2.2$×$0.6$×10-1 = $9.4.2$ kN
Vo = (*Ik12 0,6*|*0,3*) VR = $9.5.2$ kN
- along axis X
VR = 0,58 (*Kl4 jpv *)AV fd = 0,58×(*Kl4 $9.1.1$×*)$9.2.1$×$0.6$×10-1 = $9.4.1$ kN
Vo = 0,3 VR = $9.5.1$ kN
shearing conditions:
- shearing along axis Y: V = $WarY$ = VR
- shearing along axis X: V = $WarX$ = VR
jeremyclarksoooon