P27_043.PDF

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Chapter 27 - 27.43
43. (a) Using Table 27-1 and Eq. 27-10 (or Eq. 27-11), we have
= ρ
J
= 1 . 69
×
10 − 8 Ω
·
m 2 . 0A
2 . 0
×
10 − 6 m 2 =1 . 7
×
10 − 2 V / m .
(b) Using L =4 . 0 m, the resistance is found from Eq. 27-16: R = ρL/A =0 . 034 Ω. The rate of thermal
energy generation is found from Eq. 27-22: P = i 2 R =0 . 14 W. Assuming a steady rate, the thermal
energy generated in 30 minutes is (0 . 14 J / s)(30
×
60 s) = 2 . 4
×
10 2 J.
E

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