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Chapter 44 - 44.6

6. We consider the process 98 Mo

→

49 Sc + 49 Sc. The disintegration energy is Q =( m Mo −

2 m Sc ) c 2 =

2(48 . 95002 u)](931 . 5MeV / u) = +5 . 00 MeV . The fact that it is positive does not necessarily

mean we should expect to ﬁnd a great deal of Molybdenum nuclei spontaneously ﬁssioning; the energy

barrier (see Fig. 44-3) is presumably higher and/or broader for Molybdenum than for Uranium.

−

[97 . 90541u