P30_026.PDF

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Chapter 30 - 30.26
26. Using Eq. 30-15, the force on, say, wire 1 (the wire at the upper left of the figure)is along the diagonal
(pointing towards wire 3 which is at the lower right). Only the forces (or their components) along the
diagonal direction contribute. With θ =45 , we find
F 1 =
cos 45 +
µ 0 i 2
2 2 πa
=0 . 338 µ 0 i 2
a
.
F 12 + F 13 + F 14
=2 F 12 cos θ + F 13
=2 µ 0 i 2
2 πa
 
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