P22_024.PDF
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Chapter 22 - 22.24
24. With
F
=
m
e
g
, Eq. 22-1 leads to
ke
2
m
e
g
=
8
.
99
×
10
9
N
·
m
2
/
C
2
1
.
60
×
10
−
19
C
2
r
2
=
(9
.
11
×
10
−
31
kg) (9
.
8m
/
s
2
)
which leads to
r
=5
.
1 m. The second electron should be below the first one, so that the repulsive force
(acting on the first) is in the direction opposite to the pull of Earth’s gravity.
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