P22_024.PDF

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Chapter 22 - 22.24
24. With F = m e g , Eq. 22-1 leads to
ke 2
m e g =
8 . 99
×
10 9 N
·
m 2 / C 2 1 . 60
×
10 − 19 C 2
r 2 =
(9 . 11
×
10 − 31 kg) (9 . 8m / s 2 )
which leads to r =5 . 1 m. The second electron should be below the first one, so that the repulsive force
(acting on the first) is in the direction opposite to the pull of Earth’s gravity.
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