P22_003.PDF

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Chapter 22 - 22.3
3. (a) With a understood to mean the magnitude of acceleration, Newton’s second and third laws lead to
m 2 a 2 = m 1 a 1 =
m 2 = 6 . 3
×
10 − 7 kg 7 . 0m / s 2
9 . 0m / s 2
=4 . 9
×
10 − 7 kg .
(b) The magnitude of the (only) force on particle 1 is
F = m 1 a 1 = k |
q 1 ||
q 2 |
r 2
= 8 . 99
10 9 |
q
|
2
×
.
0 . 0032 2
Inserting the values for m 1 and a 1 (see part (a)) we obtain
|
q
|
=7 . 1
×
10 − 11 C .
⇒
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