p19_106.pdf
(
64 KB
)
Pobierz
Chapter 19 - 19.106
106. We use
Q
=
cm
∆
T
and
m
=
ρV
. The volume of water needed is
V
=
m
Q
ρC
∆
T
=
(1
.
00
×
10
6
kcal
/
day)(5days)
22
.
0
◦
C)
=35
.
7m
3
.
(1
.
00
×
10
3
kg
/
m
3
)(1
.
00kcal
/
kg)(50
.
0
◦
C
−
ρ
=
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Inne pliki z tego folderu:
p19_102.pdf
(66 KB)
P19_002.PDF
(57 KB)
P19_001.PDF
(63 KB)
P19_003.PDF
(70 KB)
P19_005.PDF
(65 KB)
Inne foldery tego chomika:
chap01
chap02
chap03
chap04
chap05
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