p19_104.pdf

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Chapter 19 - 19.104
104. The energy (which was originally in the form K = 2 mv 2 ) dissipated as a result of friction melts a
portion of mass m . Therefore,
1
2 (50 . 0 kg)(5 . 38m / s) 2 = mL F
723J = m (333 kJ / kg
which, for consistency of the energy units, is best written 723J = m (333 J / g). This yields m =2 . 17 g.

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