p19_011.pdf
(
65 KB
)
Pobierz
Chapter 19 - 19.11
10
−
6
/
C
◦
,
according to Table 19–2). The range of values for the diameters can be found by setting ∆
T
equal to
the temperature range. Thus ∆
D
=(3
.
2
×
×
10
−
6
/
C
◦
)(200 in
.
)(60 C
◦
)=3
.
84
×
10
−
2
in. Since 1 in
.
=
2
.
50 cm = 2
.
50
×
10
4
µ
m, this is 960
µ
m.
11. When the temperature changes from
T
to
T
+∆
T
the diameter of the mirror changes from
D
to
D
+∆
D
,
where ∆
D
=
αD
∆
T
.Here
α
is the coecient of linear expansion for Pyrex glass (3
.
2
Plik z chomika:
kf.mtsw
Inne pliki z tego folderu:
p19_102.pdf
(66 KB)
P19_002.PDF
(57 KB)
P19_001.PDF
(63 KB)
P19_003.PDF
(70 KB)
P19_005.PDF
(65 KB)
Inne foldery tego chomika:
chap01
chap02
chap03
chap04
chap05
Zgłoś jeśli
naruszono regulamin