p11_027.pdf
(
87 KB
)
Pobierz
Chapter 11 - 11.27
27. (a) Earth makes one rotation per day and 1
d
is (24 h)(3600 s
/
h) = 8
.
64
×
10
4
s, so the angular speed
ofEarth is
2
π
rad
8
.
64
ω
=
×
10
4
s
=7
.
27
×
10
−
5
rad
/
s
.
(b) We use
v
=
ωr
,where
r
is the radius ofits orbit. A point on Earth at a latitude of40
◦
moves along
a circular path ofradius
r
=
R
cos 40
◦
,where
R
is the radius ofEarth (6
.
37
×
10
6
m). Therefore,
its speed is
v
=
ω
(
R
cos 40
◦
)=
7
.
27
×
10
−
5
rad
/
s
6
.
37
×
10
6
m
cos 40
◦
= 355 m
/
s
.
(c) At the equator (and all other points on Earth) the value of
ω
isthesame(7
.
27
×
10
−
5
rad
/
s).
(d) The latitude is 0
◦
and the speed is
v
=
ωR
=
7
.
27
×
10
−
5
rad
/
s
6
.
37
×
10
6
m
= 463 m
/
s
.
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