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Chapter 1 - 1.36

36. (a) For the minimum (43 cm) case, 9cubit converts as follows:

(9cubit) 0 . 43m

1cubit

=3 . 9m .

Andfor the maximum (43 cm) case we obtain

(9cubit) 0 . 53 m

1cubit

=4 . 8m .

(b) Similarly, with 0 . 43m

→

430mm and0 . 53m

→

530mm, we ﬁnd3 . 9

×

10 3 mm and4 . 8

×

10 3 mm,

respectively.

(c) We can convert length anddiameter ﬁrst andthen compute the volume, or ﬁrst compute the volume

andthen convert. We proceedusing the latter approach (where d is diameter and is length).

4 d 2 = 28 cubit 3

= 28cubit 3 0 . 43m

1cubit

3

=2 . 2m 3

.

Similarly, with 0 . 43m replacedby 0 . 53m, we obtain V cylinder , max =4 . 2m 3 .

V cylinder , min = π