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CHAPTER 55
PUMPS AND FANS
William A. Smith
College of Engineering
University of South Florida
Tampa, Florida
55.1
PUMPANDFANSIMILARITY
1681
55.3.5 Modeling of Rotating
Fluid Machines
1691
55.3.6 Summary of Modeling
Laws
55.2 SYSTEM DESIGN: THE FIRST
STEP IN PUMP OR FAN
SELECTION
1691
1682
55.2.1 Fluid System Data
Required
55.4 PUMPSELECTION
1692
1682
55.4.1 Basic Types: Positive
Displacement and
Centrifugal (Kinetic)
55.2.2 Determination of Fluid
Head Required
1682
1692
55.2.3 Total Developed Head of
a Fan
55.4.2 Characteristics of Positive
Displacement Pumps
1684
1692
55.2.4 Engineering Data for
Pressure Loss in Fluid
Systems
55.4.3 Characteristics of
Centrifugal Pumps
1693
1684
55.4.4 Net Positive Suction Head
(NPSH)
55.2.5 Systems Head Curves
1684
1693
55.4.5 Selection of Centrifugal
Pumps
1693
55.3 CHARACTERISTICS OF
ROTATING FLUID
MACHINES
55.4.6 Operating Performance of
Pumps in a System
1694
1687
55.4.7 Throttling versus Variable
Speed Drive
55.3.1 Energy Transfer in
Rotating Fluid
Machines
1695
1687
55.3.2 Nondimensional
Performance
Characteristics of Rotating
Fluid Machines
55.5 FANSELECTION
1696
55.5.1 Types of Fans; Their
Characteristics
1696
1687
55.5.2 Fan Selection
1696
55.3.3 Importance of the Blade
Inlet Angle
55.5.3 Control of Fans for
Variable Volume
Service
1689
55.3.4 Specific Speed
1690
1698
55.1 PUMP AND FAN SIMILARITY
The performance characteristics of centrifugal pumps and fans (i.e., rotating fluid machines) are
described by the same basic laws and derived equations and, therefore, should be treated together
and not separately. Both fluid machines provide the input energy to create flow and a pressure rise
in their respective fluid systems and both use the principle of fluid acceleration as the mechanism to
add this energy. If the pressure rise across a fan is small (5000 Pa), then the gas can be considered
as an incompressible fluid, and the equations developed to describe the process will be the same as
for pumps.
Compressors are used to obtain large increases in a gaseous fluid system. With such devices the
compressibility of the gas must be considered, and a new set of derived equations must be developed
to describe the compressor's performance. Because of this, the subject of gas compressors will be
included in a separate chapter.
Mechanical Engineers' Handbook, 2nd ed., Edited by Myer Kutz.
ISBN 0-471-13007-9 © 1998 John Wiley & Sons, Inc.
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55.2 SYSTEM DESIGN: THE FIRST STEP IN PUMP OR FAN SELECTION
55.2.1 Fluid System Data Required
The first step in selecting a pump or fan is to finalize the design of the piping or duct system (i.e.,
the "fluid system") into which the fluid machine is to be placed. The fluid machine will be selected
to meet the flow and developed head requirements of the fluid system. The developed head is the
energy that must be added to the fluid by the fluid machine, expressed as the potential energy of a
column of fluid having a height H p (meters). H p is the "developed head." Consequently, the following
data must be collected before the pump or fan can be selected:
1. Maximum flow rate required and variations expected
2. Detailed design (including layout and sizing) of the pipe or duct system, including all elbows,
valves, dampers, heat exchangers, filters, etc
3. Exact location of the pump or fan in the fluid system, including its elevation
4. Fluid pressure and temperature available at start of system (suction)
5. Fluid pressure and temperature required at end of system (discharge)
6. Fluid characteristics (density, viscosity, corrosiveness, and erosiveness)
55.2.2 Determination of Fluid Head Required
The fluid head required is calculated using both the Bernoulli and D'Arcy equations from fluid
mechanics. The Bernoulli equation represents the total mechanical (nonthermal) energy content of
the fluid at any location in the system:
E TW = P 1 V 1 + Z lg + V\I2
(55.1)
where £ r(1 ) = total energy content of the fluid at location (1), J/kg
P 1 = absolute pressure of fluid at (1), Pa
U 1 = specific volume of fluid at (1), m 3 /kg
Z 1 = elevation of fluid at (1), m
g = gravity constant, m/sec 2
V 1 = velocity of fluid at (1), m/sec
The D'Arcy equation expresses the loss of mechanical energy from a fluid through friction heating
between any two locations in the system:
uAPX/j) = f L e (i - j) V 2 /2D
J/kg-m
(55.2)
where u = average fluid specific volume between two locations (i and j) in the system, m 3 /kg
APyfty) = pressure loss due to friction between two locations (i andy) in the system, Pa
/ = Moody's friction factor, an empirical function of the Reynolds number and the pipe
roughness, nondimensional
L e (i ~ j) = equivalent length of pipe, valves, and fittings between two locations i andy in the
system, m
D = pipe internal diameter (i.d.), m
An example best illustrates the method.
Example 55.1
A piping system is designed to provide 2.0 m 3 /sec of water (Q) to a discharge header at a pressure
of 200 kPa. Water temperature is 2O 0 C. Water viscosity is 0.0013 N-sec/m 2 . Pipe roughness is 0.05
mm. The gravity constant (g) is 9.81 m/sec 2 . Water suction is from a reservoir at atmospheric
pressure (101.3 kPa). The level of the water in the reservoir is assumed to be at elevation 0.0 m. The
pump will be located at elevation 1.0 m. The discharge header is at elevation 50.0 m. Piping from
the reservoir to the pump suction flange consists of the following:
1 20 m length of 1.07 m i.d. steel pipe
3 90° elbows, standard radius
2 gate valves
1 check valve
1 strainer
815043221.005.png
Piping from the pump discharge flange to the discharge header inlet flange consists of the fol-
lowing:
1 100 m length of 1.07 m i.d. steel pipe
4 90° elbows, standard radius
1 gate valve
1 check valve
Determine the "total developed head," H p (m), required of the pump.
Solution:
Let location (1) be the surface of the reservoir, the system "suction location."
Let location (2) be the inlet flange of the pump.
Let location (3) be the outlet flange of the pump.
Let location (4) be the inlet flange to the discharge header, the system "discharge location."
By energy balances
E r(1 ) - VbPf(I - 2) = E T(2}
E T(2 ) + Ep = E T py
E T{3} - uAP/3 - 4) = E TW
where E p is the energy input required by the pump. When E p is described as the potential energy
equivalent of a height of liquid, this liquid height is the "total developed head" required of the pump.
H p = E p /gm
where H p = total developed head, m.
For the data given, assuming incompressible flow:
P 1 - 101.3 kPa Z 2 - +1.Om
U 1 - 0.001 m 3 /kg = constant Z 3 = +1.Om
Z 1 = 0.0 m Z 4 = +50.0 m
V 1 - 0.0 m/sec P 4 - 200 kPa
A p = internal cross sectional area of the pipe, m 2
V 2 = Q/A = (2.0)(4)/ir(1.07) 2 = 2.22 m/sec
Assume V 3 = V 4 = V 2 = 2.22 m/sec
Viscosity (JUL) = 0.0013 N • sec/m 2
Reynolds number = D V/V[L
= (1.07)(2.22)/(0.001)(0.0013) - 1.82 X 10
Pipe roughness (e) = 0.05 mm
e/D - 0.05/(1000)(1.07) = 0.000047
From Moody's chart, / = 0.009 (see references on fluid mechanics)
From tables of equivalent lengths (see references on fluid mechanics):
Fitting
Equivalent Length, L 6 (m)
Elbow
1.6
Gate valve (open)
0.3
Check valve
0.3
Strainer
1.8
815043221.006.png
L e (l-2) - 20 + (3)(1.6) + 2(0.3) + 0.3 + 1.8 - 27.5 m
4(3-4) = 100 + (4)(1.6) + 0.3 + 0.3 = 107.0 m
uAP(l-2) - (0.009)(27.5)(2.22) 2 /(2)(1.07) = 0.57 J/kg
uAP(3-4) = (0.009)(107.0)(2.22) 2 /(2)(1.07) - 2.21 J/kg
E TW = P 1 V 1 + Z + Vf/2
- (101,300)(0.001) + O + O - 101.30 J/kg
E Tm = E r( i> - uAP/1-2)
= 101.3 - 0.57 - 100.7 J/kg
E r(4 ) = P 4 V 4 + Z 4 g + V 2 4 /2
= (200,000)(0.001) + (50.0)(9.81) + (2.22) 2 /2
- 692.9 J/kg
ET-O) = ETW + "AP/3-4)
- 692.9 + 2.21 - 695.1 J/kg
E p = £7-( 3 ) ~~ E r(2 )
- 695.1 - 100.7 = 594.4 J/kg
H p = E p /g = 594.4/9.81 - 60.6 m of water
It is seen that a pump capable of providing 2.0 m 3 /sec flow with a developed head of 60.6 m of
water is required to meet the demands of this fluid system.
55.2.3 Total Developed Head of a Fan
The procedure for finding the total developed head of a fan is identical to that described for a pump.
However, the fan head is commonly expressed in terms of a height of water instead of a height of
the gas being moved, since water manometers are used to measure gas pressures at the inlet and
outlet of a fan. Consequently,
H fw = (p s / P JH fg
where H fw = developed head of the fan, expressed as a head of water, m
H fg = developed head of the fan, expressed as a head of the gas being moved, m
p g = density of gas, kg/m 3
p w = density of water in manometer, kg/m 3
As an example, if the head required of a fan is found to be 100 m of air by the method described
in Section 55.2.2, the air density is 1.21 kg/m 3 , and the water density in the manometer is 1000
kg/m 3 , then the developed head, in terms of the column of water, is
H fw = (1.21/100O)(IOO) - 0.121 m of water
In this example the air is assumed to be incompressible, since the pressure rise across the fan
was small (only 0.12 m of water, or 1177 Pa).
55.2.4 Engineering Data for Pressure Loss in Fluid Systems
In practice, only rarely will an engineer have to apply the D'Arcy equation to determine pressure
losses in fluid systems. Tables and figures for pressure losses of water, steam, and air in pipe and
duct systems are readily available from a number of references. (See Figs. 55.1 and 55.2.)
55.2.5 Systems Head Curves
A systems head curve is a plot of the head required by the system for various flow rates through the
system. This plot is necessary for analyzing system performance for variable flow application and is
desirable for pump and fan selection and system analysis for constant flow applications.
The curve to be plotted is H versus Q, where
H=[E T(3} -E T(2} ]/g (55.3)
Assume that V 1 = O and V = V 4 in Eqs. (55.1) and (55.2), and letting V = Q/A, then Eq. (55.3)
reduces to
815043221.001.png
Fig. 55.1 Friction loss for water in commercial steel pipe (schedule 40). (Courtesy of American Society of Heating, Refrigerating and Air Conditioning Engineers.)
815043221.002.png
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